Question

The breaking force of plastic bags used to package products is normally distributed with a mean of 5 pounds per inch. square and a standard deviation of 1.5 pounds per square inch. d. Between which two values symmetrically distributed around the mean will 95% of the breaking forces lie?

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Answer to a math question The breaking force of plastic bags used to package products is normally distributed with a mean of 5 pounds per inch. square and a standard deviation of 1.5 pounds per square inch. d. Between which two values symmetrically distributed around the mean will 95% of the breaking forces lie?

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Esmeralda

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\text{Media (\mu)} = 5 \text{ libras por pulgada cuadrada}

\text{Desviación estándar (\sigma)} = 1.5 \text{ libras por pulgada cuadrada}

\text{Para un 95\% de confianza, usamos el valor crítico } z = 1.96

Límite inferior = \mu - z\sigma = 5 - 1.96 \times 1.5 = 2.06

Límite superior = \mu + z\sigma = 5 + 1.96 \times 1.5 = 7.94

\text{Valores: } 2.06 \text{ y } 7.94 \text{ libras por pulgada cuadrada}

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