Question

The machine M produces a product P. From the two years I and II it is known that the unit costs for manufacturing the product in the first year are kI  €42.50 and in the second year kII  €41.00. In year I 2 000 units were produced and in year II 2 500 units were produced. a) What are the values of m and b if the total costs K result from the quantity x according to the equation K(x)  m · x  b and this applies to both years I and II? State the values for m and b as well as the cost function with the values for m and b.

249

likes
1244 views

Answer to a math question The machine M produces a product P. From the two years I and II it is known that the unit costs for manufacturing the product in the first year are kI  €42.50 and in the second year kII  €41.00. In year I 2 000 units were produced and in year II 2 500 units were produced. a) What are the values of m and b if the total costs K result from the quantity x according to the equation K(x)  m · x  b and this applies to both years I and II? State the values for m and b as well as the cost function with the values for m and b.

Expert avatar
Hester
4.8
116 Answers
Given that the total costs are represented by the equation K(x) = m \cdot x + b, where x is the quantity produced, m is the unit cost, and b is a constant term.

For year I, the total cost is given by K_I(x) = k_I \cdot 2000 = 42.50 \cdot 2000 = 85,000 euros.
For year II, the total cost is given by K_{II}(x) = k_{II} \cdot 2500 = 41.00 \cdot 2500 = 102,500 euros.

Since the equation K(x) = m \cdot x + b applies to both years I and II:
1. For year I: K_I(x) = m \cdot 2000 + b
2. For year II: K_{II}(x) = m \cdot 2500 + b

By substituting the known values:
1. For year I: 85,000 = 2000m + b
2. For year II: 102,500 = 2500m + b

Solving these two equations simultaneously to find the values of m and b:
From equation 1: b = 85,000 - 2000m
Substitute b into equation 2: 102,500 = 2500m + 85,000 - 2000m
102,500 = 2500m + 85,000 - 2000m
102,500 = 500m + 85,000
500m = 17,500
m = 35

Substitute m = 35 back into b = 85,000 - 2000m:
b = 85,000 - 2000 \times 35
b = 85,000 - 70,000
b = 15,000

Therefore, the values for m and b are:
m = 35
b = 15,000

The cost function with the values for m and b is:
K(x) = 35x + 15,000 euros.

\boxed{m = 35, \ b = 15,000, \ K(x) = 35x + 15,000}

Frequently asked questions (FAQs)
Math Question: Find the square root of 169 using the table given.
+
Math question: What is the equation of the parabola if its vertex is (2, -3) and it passes through the point (4, 5)?
+
What is the y-intercept of the graph of the exponential function y = 2^x?
+
New questions in Mathematics
Let f(x)=||x|−6|+|15−|x|| . Then f(6)+f(15) is equal to:
Let the vectors be u=(-1,0,2) , v=(0,2,-3) , w=(2,2,3) Calculate the following expressions a)<u,w> b) &lt;2u- 5v,3w&gt;
A circle with a 12-inch diameter is folded in half and then folded in half again. What is the area of the resulting shape?
Solve: −3(−2x+23)+12=6(−4x+9)+9.
Determine all solutions to the inequality |2x + 6| − |x + 1| < 6. Write your final answer in interval notation
(-5/6)-(-5/4)
-27=-7u 5(u-3)
The physician orders 15mg of tramadol(liquid). On hand is 30mg/2mL vials. How many mL will the MA administer?
Engineers want to design seats in commercial aircraft so that they are wide enough to fit ​95% of all males.​ (Accommodating 100% of males would require very wide seats that would be much too​ expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.2 in. Find P95. That​ is, find the hip breadth for men that separates the smallest ​95% from the largest 5​%.
Use a pattern to prove that (-2)-(-3)=1
9 x² + 2x + 1 = 0
2x2
Two particles of electrical charges Q1=3.8×10-⁶C and q,=4.4×10-⁶C are separated in vacuum by a distance of 4.0.10-⁸ m. Since K=9.0.10⁹ N.m²/C², the intensity of the interaction force between them, in newtons, is?
Calculate the change in internal energy of a gas that receives 16000 J of heat at constant pressure (1.3 atm) expanding from 0.100 m3 to 0.200 m3. Question 1Answer to. 7050J b. 2125J c. None of the above d. 2828J and. 10295 J
For the numbers below, select a number at random and find the probability that: a. The number is even b. The sum of the number’s digit is even c. The number is greater than 50 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
Consider the function f(x)=1/2(x+1)^2-3. Use the preceding/following interval method to estimate the instantaneous rate of change at 𝑥 = 1.
56 × 12 = 672. How should you adjust this answer 672 to determine 57 × 12? a) The answer increases by 1 b) The answer increases by 57 c) The answer increases by 56 d) The answer increases by 12
Sodium 38.15 38.78 38.5 38.65 38.79 38.89 38.57 38.59 38.59 38.8 38.63 38.43 38.56 38.46 38.79 38.42 38.74 39.12 38.5 38.42 38.57 38.37 38.71 38.71 38.4 38.56 38.39 38.34 39.04 38.8 A supplier of bottled mineral water claims that his supply of water has an average sodium content of 36.6 mg/L. The boxplot below is of the sodium contents levels taken from a random sample of 30 bottles. With this data investigate the claim using SPSS to apply the appropriate test. Download the data and transfer it into SPSS. Check that your data transfer has been successful by obtaining the Std. Error of the mean for your data which should appear in SPSS output as 0.03900.. If you do not have this exact value, then you may have not transferred your data from the Excel file to SPSS correctly. Do not continue with the test until your value agrees as otherwise you may not have correct answers. Unless otherwise directed you should report all numeric values to the accuracy displayed in the SPSS output that is supplied when your data has been transferred correctly. In the following questions, all statistical tests should be carried out at the 0.05 significance level. Sample mean and median Complete the following concerning the mean and median of the data. mean =  mg/L 95% CI:  to  mg/L Based upon the 95% confidence interval, is it plausible that the average sodium content is 36.9 mg/L?      median:  mg/L The median value is      36.9 mg/L. Skewness Complete the following concerning the skewness of the data. Skewness statistic =        Std. Error =  The absolute value of the skewness statistic     less than 2 x Std. Error Therefore the data can be considered to come from a population that is      . Normality test Complete the following summary concerning the formal testing of the normality of the data. H0: The data come from a population that     normal H1: The data come from a population that     normal Application of the Shapiro-Wilk test indicated that the normality assumption     reasonable for sodium content (S-W(  )=  , p=   ). Main test Using the guidelines you have been taught that consider sample size, skewness and normality, choose and report the appropriate main test from the following ( Appropriate ONE ) You have selected that you wish to report the one-sample t-test. H0: The mean sodium content     equal to 36.9 mg/L H1: The mean sodium content     equal to 36.9 mg/L Application of the one-sample t-test indicated that the mean is      36.9 mg/L (t(  ) =  , p =   ). You have selected that you wish to report the Wilcoxon signed rank test. H0: The median sodium content     equal to 36.9 mg/L H1: The median sodium content     equal to 36.9 mg/L Application of the Wilcoxon signed rank test indicated that the median is      36.9 mg/L (z =  , N =  , p =   ).
The supply of a good registers periodic increases. With each increase in the offer, the total receipts of the bidders increase. Indicate the correct statement: a) demand is elastic b) demand is inelastic c) supply is inelastic d) supply has unit elasticity.
A gas is leaking at 3.5ft3/min in a room of 2.9m by 6.9ft by 15.7m. How long would it take (in seconds) for 22% of the room to reach the LFL, if the gas has a LFL of 2.51%?