Three cars leave a city simultaneously, the first every 12 days, the second every 5 days and the third every 17 days. If they start their journey on January 5th from a single starting point, on which two future dates will they coincide in their departure?

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Answer to a math question Three cars leave a city simultaneously, the first every 12 days, the second every 5 days and the third every 17 days. If they start their journey on January 5th from a single starting point, on which two future dates will they coincide in their departure?

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El mínimo común múltiplo de 5,12,17 es 5\cdot12\cdot17=1020 días. 1020 días equivalen a 2 años + 290 días y 290 días después del 5 de enero de 2024 es el 21 de octubre de 2026. Entonces, la fecha es el 21 de octubre.

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Three cars leave a city simultaneously, the first every 12 days, the second every 5 days and the third every 17 days. If they start their journey on January 5th from a single starting point, on which two future dates will they coincide in their departure?

Answer to a math question Three cars leave a city simultaneously, the first every 12 days, the second every 5 days and the third every 17 days. If they start their journey on January 5th from a single starting point, on which two future dates will they coincide in their departure?

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