What is the algebraic expression that corresponds to the sum of three consecutive numbers of 91?

1. Denote three consecutive numbers as \( x \), \( x+1 \), and \( x+2 \).
2. Set up the equation:
x + (x+1) + (x+2) = 91
3. Simplify:
x + x + 1 + x + 2 = 91
4. Combine like terms:
3x + 3 = 91
5. Subtract 3 from both sides:
3x = 88
6. Divide by 3:
x = \frac{88}{3}

Since \( x \) must be an integer and isn't, recheck the problem's integers might be necessary.