Given set π = {β2; 1; 0; 1/2; 3/4; 2; 10/3; 4; β5}
a) {π₯ β π/π₯ - 4 < 0}
To solve this, first, we need to find the elements in π where π₯ - 4 < 0.
π₯ - 4 < 0
π₯ < 4
The elements in set π that satisfy π₯ < 4 are {-2; 1; 0; 1/2; 3/4; 2, 10/3}.
b) {π₯ β π/π₯^2 - 6π₯ + 8 < 0}
To solve this, first, we need to find the elements in π where π₯^2 - 6π₯ + 8 < 0.
(π₯ - 4)(π₯ - 2) < 0
The solutions to this inequality are π₯ β (2, 4).
Thus, the elements in set π that satisfy this inequality are {3/4}.
c) {π₯ β π/4 - π₯ β€ 0}
To solve this, first, we need to find the elements in π where 4 - π₯ β€ 0.
4 - π₯ β€ 0
π₯ β₯ 4
The only element in set π that satisfies this inequality is {4}.
d) {π₯ β π/π₯^2 + 1 β€ 0}
To solve this, first, we need to find the elements in π where π₯^2 + 1 β€ 0.
This inequality has no real solutions because π₯^2 + 1 is always greater than 0 for all real values of π₯.
Therefore, there are no elements in π that satisfy this inequality.
\textbf{Answer:}
a) {-2; 1; 0; 1/2; 3/4; 2; 10/3}
b) {3/4}
c) {4}
d) No elements in set π satisfy the inequality.