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5a/10b-10b2+8 Where a =-8 and b=-6

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Answer to a math question 5a/10b-10b2+8 Where a =-8 and b=-6

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Gerhard
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86 Answers
1. Substitute \( a = -8 \) and \( b = -6 \) into the expression:

\frac{5(-8)}{10(-6)} - 10(-6)^2 + 8

2. Simplify \( \frac{5(-8)}{10(-6)} \) :

\frac{5 \times (-8)}{10 \times (-6)} = \frac{-40}{-60} = \frac{2}{3}

3. Calculate \( 10(-6)^2 \) :

10 \times (-6)^2 = 10 \times 36 = 360

4. Substitute these values back into the expression:

\frac{2}{3} - 360 + 8

5. Combine the terms carefully:

\frac{2}{3} + 8 = \frac{2}{3} + \frac{24}{3} = \frac{26}{3}

6. Subtract 360:

\frac{26}{3} - 360 = \frac{26}{3} - \frac{1080}{3} = \frac{26 - 1080}{3} = \frac{-1054}{3}

7. Final result is:

\frac{-1054}{3}

The answer is \(-\frac{1054}{3}\).

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