To solve this system of equations, we can use the method of elimination.
Step 1: Multiply the second equation by 2 to make the coefficients of x in both equations the same:
-6x + 3y = -12
-6x + 6y = 6
Step 2: Now we can eliminate the x terms by subtracting the second equation from the first:
(-6x + 6y) - (-6x + 3y) = 6 - (-12)
-6x + 6y + 6x - 3y = 6 + 12
3y = 18
Step 3: Simplify the equation:
3y = 18
Step 4: Solve for y by dividing both sides of the equation by 3:
\frac{{3y}}{{3}} = \frac{{18}}{{3}}
y = 6
Step 5: Substitute the value of y back into one of the original equations. Let's use the first equation:
-6x + 6y = 6
-6x + 6(6) = 6
-6x + 36 = 6
Step 6: Solve for x:
-6x = 6 - 36
-6x = -30
x = \frac{{-30}}{{-6}}
x = 5
Answer: The solution to the system of equations is x = 5 and y = 6.