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Describe a real-life situation that can be modeled by a function (a relation in which every input value corresponds to only one output value). The situation must be different from the examples provided in the reading and in the homework. Identify the input value and the output value of the function, and provide justification that your relation does, in fact, represent a function. 2. Create a function in the form y = f(x) that models the relation described. You may choose variables in place of y or x that better represent the relation, as seen in the provided example. 3. Identify the domain and range of your function, using proper mathematical notation.

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Answer to a math question Describe a real-life situation that can be modeled by a function (a relation in which every input value corresponds to only one output value). The situation must be different from the examples provided in the reading and in the homework. Identify the input value and the output value of the function, and provide justification that your relation does, in fact, represent a function. 2. Create a function in the form y = f(x) that models the relation described. You may choose variables in place of y or x that better represent the relation, as seen in the provided example. 3. Identify the domain and range of your function, using proper mathematical notation.

Expert avatar
Nash
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87 Answers
Real-life Situation:
A car rental company charges a fixed fee for renting a car for a certain number of days, and an additional daily rate for any extra days beyond the initial rental period.

Function Representation:
Let's say we have a car rental company that charges a fixed fee of $50 for renting a car for up to 3 days, and an additional $10 per day for any extra days beyond the initial rental period.

Input and Output Values:
In this situation, the input value would be the number of days a car is rented for, denoted by x. The output value would be the total cost of renting the car for those number of days, denoted by y.

Function Representation:
To create a function that models this relationship, we can use the piecewise function notation:

y = \begin{cases} 50 & \text{if } x \leq 3 \ 50 + 10(x-3) & \text{if } x > 3 \end{cases}

This function can be read as follows: for x less than or equal to 3, the cost of renting the car is $50. For x greater than 3, the cost is $50 plus $10 for each extra day beyond 3.

Domain and Range:
The domain of this function would be the set of possible values for x, which in this case would be the set of positive integers representing the number of days a car is rented for: D = \{1, 2, 3, 4, 5, ...\}

The range of this function would be the set of possible values for y, which in this case would be the set of positive integers representing the total cost of renting a car for a given number of days: R = \{50, 60, 70, 80, ...\}

Answer: The real-life situation of a car rental company can be modeled by the function y = \begin{cases} 50 & \text{if } x \leq 3 \ 50 + 10(x-3) & \text{if } x > 3 \end{cases} . The domain is D = \{1, 2, 3, 4, 5, ...\} and the range is R = \{50, 60, 70, 80, ...\} .

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