Question

Find the area under the curve of f(x)=3x^2+2x in the interval 0.6

244

likes1218 views

Timmothy

4.8

51 Answers

To find the area under the curve of the function f(x) = 3x^2 + 2x in the interval (0,6), we need to find the definite integral of the function over the interval (0,6).

We have:

\int_{0}^{6} (3x^2 + 2x) \, dx

Now, we integrate the function:

\int_{0}^{6} (3x^2 + 2x) \, dx = \left[ x^3 + x^2 \right]_{0}^{6}

= (6^3 + 6^2) - (0 + 0)

= (216 + 36) - 0

= 252

So, the area under the curve of f(x) = 3x^2 + 2x in the interval (0,6) is \boxed{252} .

We have:

Now, we integrate the function:

So, the area under the curve of

Frequently asked questions (FAQs)

What is the derivative of f(x) = 3x^4 - 2x^3 + 5x^2 - 7x + 10 with respect to x?

+

What is the equation of the ellipse with a major axis of length 8 units, a minor axis of length 6 units, and centered at the origin?

+

What is the limit of (x^2 - 4x + 3) / (x - 3) as x approaches 3?

+

New questions in Mathematics