1. Identify the formula for the sum of the first \( n \) natural numbers:
S = \frac{n(n + 1)}{2}
2. Substitute \( n = 790 \):
S = \frac{790(790 + 1)}{2}
3. Perform the multiplication inside the bracket first:
790 + 1 = 791
4. Multiply 790 by 791:
790 \times 791 = 624290
5. Divide 624290 by 2:
\frac{624290}{2}=312445
Therefore, the sum of the whole numbers from 1 to 790 is:
312445