Question
Two particles of different masses are separated by 1000 m in space, if the mass of particle A is equal to 1050 g and the mass of particle B is equal to 80 kg. Calculate the gravitational force considering that the universal gravitational constant is 6.67x10-11 m3/kg s2. Express the result in Newtons.
238
likes1188 views
Answer to a math question Two particles of different masses are separated by 1000 m in space, if the mass of particle A is equal to 1050 g and the mass of particle B is equal to 80 kg. Calculate the gravitational force considering that the universal gravitational constant is 6.67x10-11 m3/kg s2. Express the result in Newtons.
Gene
4.5108 Answers
1. Convertir la masa de A a kilogramos:
m_A = 1050 \ \text{g} = 1.050 \ \text{kg}
2. La masa de B ya está en kilogramos:
m_B = 80 \ \text{kg}
3. La distancia entre las partículas es:
r = 1000 \ \text{m}
4. La constante de gravitación universal es:
G = 6.67 \times 10^{-11} \ \text{m}^3/\text{kg} \ \text{s}^2
5. Aplicar la fórmula de la fuerza gravitacional:
F = \frac{G \cdot m_A \cdot m_B}{r^2}
F = \frac{(6.67 \times 10^{-11}) \cdot (1.050) \cdot (80)}{(1000)^2}
F = \frac{(6.67 \times 10^{-11}) \cdot (84)}{1000000}
F=5.6\times10^{-15}\text{N}
La fuerza gravitacional es5.6\times10^{-15}\text{N}
2. La masa de B ya está en kilogramos:
3. La distancia entre las partículas es:
4. La constante de gravitación universal es:
5. Aplicar la fórmula de la fuerza gravitacional:
La fuerza gravitacional es
Frequently asked questions (FAQs)
Find the maximum value of the function f(x) = x^3 - 6x^2 + 9x on the interval [0, 4].
+
What is the area of a triangle with base length 8 units and height 15 units?
+
What is the smallest exponent n that satisfies Fermat's theorem, x^n + y^n = z^n, for positive integers x, y, and z, with n > 2?
+
New questions in Mathematics