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2 In x + x In 3 - 1/2 In (x + 1)

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Answer to a math question 2 In x + x In 3 - 1/2 In (x + 1)

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$=\ln(x^{2})+\ln(3)x-\frac{1}{2}\ln(x+1)$

$=\ln(x^{2})+\ln(3)x-\ln((x+1)^{\frac{1}{2}})$

$=\ln(\frac{x^{2}}{(x+1)^{\frac{1}{2}}})+\ln(3)x$

$=\ln(\frac{x^{2}\sqrt{x+1}}{x+1})+x\ln(3)$

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