a ladder of lent 8 1 m is propped on an horizontal ground against the vertical wall with his bottom end at a distance of 1
Question
A ladder of lent 8.1 m is propped on an horizontal ground against the vertical wall with his bottom end at a distance of 1.6 m from the wall how I up the wall is the top end. Give your answer in one decimal place.
55
likes
275 views
Answer to a math question A ladder of lent 8.1 m is propped on an horizontal ground against the vertical wall with his bottom end at a distance of 1.6 m from the wall how I up the wall is the top end. Give your answer in one decimal place.
1. Set up the equation using the Pythagorean theorem: h^2 + 1.6^2 = 8.1^2
2. Solve for \( h \) by rearranging terms: h^2 = 8.1^2 - 1.6^2
3. Calculate each square: 8.1^2 = 65.61 1.6^2 = 2.56
4. Subtract to find the square of the height: h^2 = 65.61 - 2.56 = 63.05
5. Find the square root to solve for \( h \): h = \sqrt{63.05} \approx 7.9
6. Therefore, the top end of the ladder reaches approximately 7.9 meters up the wall.
Frequently asked questions (FAQs)
\(\sqrt[3]{x^3 - 8}\) represents the cube root function. When solving this equation, we find that the value of \(x\) is equal to \(2\) for any real \(x\).
+
What is the equation of the basic shape represented by a parabola with a vertex at (2, -3)?
+
Question: What is the limit of (3x^2 + 2x - 5)/(x^2 + 3) as x approaches infinity?