Question
the equation of the line that passes through point A (4, -6) and forms an angle of 45º with the positive x axis is:
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Answer to a math question the equation of the line that passes through point A (4, -6) and forms an angle of 45º with the positive x axis is:
Seamus
4.999 Answers
1. Determinamos la pendiente \(m\)
\[
m = \tan(45^\circ) = 1
\]
2. Utilizamos la fórmula de la recta\(y = mx + b\)
\[
y = x + b
\]
3. Insertamos el punto\(A (4, -6)\) \(b\)
\[
-6 = 4 + b
\]
\[
b = -10
\]
4. Finalmente, obtenemos la ecuación de la recta:
\[
y = x - 10
\]
\[
\boxed{y = x - 10}
\]
m = \tan(45^\circ) = 1
\]
2. Utilizamos la fórmula de la recta
y = x + b
\]
3. Insertamos el punto
-6 = 4 + b
\]
b = -10
\]
4. Finalmente, obtenemos la ecuación de la recta:
y = x - 10
\]
\boxed{y = x - 10}
\]
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