The sum of 2 numbers and 16 is 5 times the difference of a number and 6 solver for the variable

Let's use algebra to represent the given information.
Let the two numbers be x and y.
According to the problem, the sum of two numbers and 16 is equal to 5 times the difference of a number and 6:
$x + y + 16 = 5(y - 6)$

Now, we can simplify and solve for the variables.
$x + y + 16 = 5y - 30$
$x + y = 5y - 46$
$x = 4y - 46$

Therefore, the variable x is equal to $4y - 46$.
\boxed{x = 4y - 46}