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A baseball player throws a 0.2 kg ball upward with a speed of 10 m/s. Calculate the kinetic energy and potential energy of the ball when it reaches its maximum height.

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Answer to a math question A baseball player throws a 0.2 kg ball upward with a speed of 10 m/s. Calculate the kinetic energy and potential energy of the ball when it reaches its maximum height.

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Darrell

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Sea positiva la dirección ascendente. a máxima altura, velocidad =0. Por tanto, la energía cinética es igual a 0. también, a = (vf-vi)/t -9,8 = (0-10)/t t = 50/49 s por eso d = vi*t +1/2*at² d = 10*50/49 +1/2*(-9,8)*(50/49)² re = 5,102 m por lo tanto, PE=mgh = 0,2*9,8*5,102 PE = 10 J

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A baseball player throws a 0.2 kg ball upward with a speed of 10 m/s. Calculate the kinetic energy and potential energy of the ball when it reaches its maximum height.

Answer to a math question A baseball player throws a 0.2 kg ball upward with a speed of 10 m/s. Calculate the kinetic energy and potential energy of the ball when it reaches its maximum height.

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