Algorithm that reads two numbers and tells us which is the largest or if they are equal, repeat the process 10 times

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Answer to a math question Algorithm that reads two numbers and tells us which is the largest or if they are equal, repeat the process 10 times

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Aquí hay un algoritmo simple (en pseudocódigo) que lee dos números, los compara y repite el proceso 10 veces para determinar qué número es mayor o si son iguales: Algoritmo: 1. Establezca `count` en 0. 2. Mientras `count < 10`: - Leer `num1` (primer número). - Leer `num2` (segundo número). - Si `num1 > num2`: - Imprimir "num1 es mayor que num2". - De lo contrario, si `num1 < num2`: - Imprimir "num2 es mayor que num1". - Demás: - Imprimir "Ambos números son iguales". - Incrementa `count` en 1. 3. Fin. Puedes implementar esto en cualquier lenguaje de programación. A continuación, se muestra un ejemplo de implementación en Python: pitón para contar en rango(10): num1 = float(input("Ingrese el primer número: ")) num2 = float(input("Ingrese el segundo número: ")) si num1 > num2: print(f"{num1} es mayor que {num2}.") elif num1 < num2: print(f"{num2} es mayor que {num1}.") demás: print("Ambos números son iguales.") Este código Python repetirá el proceso 10 veces, comparando dos números cada vez y proporcionando el resultado apropiado.

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