at constant temperature. What should be the volume of a sample of gas that is initially at 2 atm pressure and occupies a volume of 1L if the pressure is doubled?

To find the new volume of the gas when the pressure is doubled, we can use Boyle's Law:

Boyle's Law states: P_1V_1 = P_2V_2 where P_1 and V_1 are the initial pressure and volume, and P_2 and V_2 are the final pressure and volume. Since the temperature is constant, we can use Boyle's Law.

Given:
P_1 = 2 atm
V_1 = 1 L
P_2 = 2 \times P_1 = 2 \times 2 = 4 atm

Let's substitute the values into Boyle's Law formula:
P_1V_1 = P_2V_2
2 \times 1 = 4 \times V_2
2 = 4V_2

Solving for V_2 :
V_2 = \frac{2}{4}
V_2 = \frac{1}{2}
V_2 = 0.5 L

Therefore, the volume of the gas when the pressure is doubled is \boxed{0.5} L.