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exercise 2 calculating current using resistivity and ohm s law an aluminum wire 2 82 10 8 m has a length of 5 m and a cros

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Exercise 2: Calculating current using resistivity and Ohm's Law: An aluminum wire (ρ=2.82×10−8 Ω⋅m ) has a length of 5 m and a cross-section of 2 mm². It connects to a 12V power source. Question: What current will flow through the wire?

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Answer to a math question Exercise 2: Calculating current using resistivity and Ohm's Law: An aluminum wire (ρ=2.82×10−8 Ω⋅m ) has a length of 5 m and a cross-section of 2 mm². It connects to a 12V power source. Question: What current will flow through the wire?

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99 Answers

R = \rho \frac{L}{A}

R = 2.82 \times 10^{-8} \, \Omega \cdot \text{m} \times \frac{5 \, \text{m}}{2 \times 10^{-6} \, \text{m}^2}

R = 7.05 \times 10^{-2} \, \Omega

I = \frac{V}{R}

I = \frac{12 \, \text{V}}{7.05 \times 10^{-2} \, \Omega}

I = 170.21 \, \text{A}

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