Find the equation of the line A, which passes through the points (-1,5) and (2,6) Where the slope of a line m is given as m = Y2 - Y1 ———— X2 - X1 And the formule for the line is given as Y - Y, = m (x-x,)

To find the equation of the line passing through points (-1,5) and (2,6) using point-slope form, follow these steps:

1. Calculate the slope of the line using the formula:
m = \frac{{y_2 - y_1}}{{x_2 - x_1}}
where (x_1, y_1) = (-1,5) and (x_2, y_2) = (2,6) .

m = \frac{{6 - 5}}{{2 - (-1)}} = \frac{1}{3}

2. Substitute one of the points into the point-slope form equation:
y - y_1 = m(x - x_1)
Using point (-1,5):
y-5=\frac{1}{3}(x-(-1))

So, the equation of line A passing through points (-1,5) and (2,6) in point-slope form is:
\boxed{y-5=\frac{1}{3}\left(x+1\right)}