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trigonometric function: integral sen(2x)cos(4x)dx

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Answer to a math question trigonometric function: integral sen(2x)cos(4x)dx

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Darrell
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$=\int \frac{\sin(2x+4x)+\sin(2x-4x)}{2}dx$
$=\frac{1}{2}\cdot \int \sin(2x+4x)+\sin(2x-4x)dx$
$=\frac{1}{2}(\int \sin(2x+4x)dx+\int \sin(2x-4x)dx)$
$=\frac{1}{2}(-\frac{1}{6}\cos(6x)+\frac{1}{2}\cos(2x))$
$=\frac{1}{2}(-\frac{1}{6}\cos(6x)+\frac{1}{2}\cos(2x))+C$

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