Step 1: Rewrite the equation in standard form by moving all terms to one side:
2x^2 - 6x + 10 = 0
Step 2: Try factoring the quadratic equation. However, in this case, the equation cannot be factored easily.
Step 3: Use the quadratic formula to find the solutions for the equation ax^2 + bx + c = 0, where a = 2, b = -6, and c = 10.
The quadratic formula is given by:
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Substitute the values of a, b, and c:
x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4 \cdot 2 \cdot 10}}{2 \cdot 2}
x = \frac{6 \pm \sqrt{36 - 80}}{4}
x = \frac{6 \pm \sqrt{-44}}{4}
Since the square root is negative, the solutions are complex numbers. Therefore, the solutions are NOT REAL.
\boxed{\text{NOT REAL}}