Let's assume Mary originally had x .
Mary gave one third of her money to Nadeem, which is \frac{1}{3}x . After giving this amount to Nadeem, Mary had \frac{2}{3}x left.
Mary also gave one fifth of her money to Elwethu, which is \frac{1}{5}x . After giving this amount to Elwethu, Mary had \frac{4}{5}x left.
Given that Elwethu received $R28 less than Nazeem, we can set up the equation:
Nazeem's share - Elwethu's share = $28
\frac{1}{3}x - \frac{1}{5}x = 28
Solving for x:
\frac{5x-3x}{15} = 28
\frac{2x}{15} = 28
2x = 15 \times 28
x = \frac{15 \times 28}{2}
x = 210
Therefore, Mary originally had R210. \boxed{Answer}